Sentence


Parse

Does
(S[q]/(S[b]\NP))/NP
 
she
NP
 
S[q]/(S[b]\NP)
> 0
speak
(S[b]\NP)/NP
 
English
N
 
NP
*
?
.
 
NP
.
S[b]\NP
> 0
S[q]
> 0

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