Sentence


Parse

How
(S/S)/(S[adj]\NP)
 
many
S[adj]\NP
 
S/S
> 0
boys
N
 
NP
*
are
(S[dcl]\NP)/(S[adj]\NP)
 
there
S[adj]\NP
 
in
((S\NP)\(S\NP))/NP
 
this
NP/N
 
class
N
 
NP
> 0
(S\NP)\(S\NP)
> 0
S[adj]\NP
< 0
S[dcl]\NP
> 0
S[dcl]
< 0
?
.
 
S[dcl]
.
S[dcl]
> 0

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