Sentence


Parse

Da
S[dcl]/S[dcl]
 
wird
(S[dcl]\NP)/(S[ng]\NP)
 
doch
(S[dcl]\NP)\(S[dcl]\NP)
 
(S[dcl]\NP)/(S[ng]\NP)
< 1×
der
NP/N
 
Hund
N
 
in
(N\N)/NP
 
der
NP/N
 
Pfanne
N
 
NP
> 0
N\N
> 0
N
< 0
NP
> 0
S[dcl]/(S[dcl]\NP)
T >
verrückt
S[ng]\NP
 
(S[dcl]\NP)\((S[dcl]\NP)/(S[ng]\NP))
T <
S[dcl]\((S[dcl]\NP)/(S[ng]\NP))
> 1×
S[dcl]
< 0
.
S[dcl]\S[dcl]
 
S[dcl]
< 0
S[dcl]
> 0

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