Sentence


Parse

Damit
S[dcl]/S[dcl]
 
habe
(S[dcl]\NP)/NP
 
ich
NP
 
S[dcl]/(S[dcl]\NP)
T >
nichts
NP
 
(S[dcl]\NP)\((S[dcl]\NP)/NP)
T <
S[dcl]\((S[dcl]\NP)/NP)
> 1×
S[dcl]
< 0
S[dcl]
> 0
zu
(S[to]\NP)/(S[b]\NP)
 
tun
S[b]\NP
 
S[to]\NP
> 0
S[dcl]/S[dcl]
*
.
S[dcl]\S[dcl]
 
S[dcl]\S[dcl]
> 1×
S[dcl]
< 0

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