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Du
NP
kannst
(S[dcl]\NP)/(S[adj]\NP)
das
NP
,
(NP\NP)/NP
nicht
(S[adj]\NP)/(S[adj]\NP)
wahr
S[adj]\NP
S[adj]\NP
>
0
(S[adj]\NP)/NP
<
n
?
NP\NP
(S[adj]\NP)\NP
>
1
×
S[adj]\NP
<
0
S[dcl]\NP
>
0
S[dcl]
<
0
<div class="der"> <table class="constituent binaryrule" data-cat="S[dcl]"> <tr class="daughters"> <td class="daughter daughter-left"><table class="constituent lex" data-token="Du" data-from="0" data-to="2" data-cat="NP"> <tr><td class="token">Du</td></tr> <tr><td class="cat" tabindex="0">NP</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> <td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[dcl]\NP"> <tr class="daughters"> <td class="daughter daughter-left"><table class="constituent lex" data-token="kannst" data-from="3" data-to="9" data-cat="(S[dcl]\NP)/(S[adj]\NP)"> <tr><td class="token">kannst</td></tr> <tr><td class="cat" tabindex="0">(S[dcl]\NP)/(S[adj]\NP)</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> <td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[adj]\NP"> <tr class="daughters"> <td class="daughter daughter-left"><table class="constituent lex" data-token="das" data-from="10" data-to="13" data-cat="NP"> <tr><td class="token">das</td></tr> <tr><td class="cat" tabindex="0">NP</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> <td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="(S[adj]\NP)\NP"> <tr class="daughters"> <td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="(S[adj]\NP)/NP"> <tr class="daughters"> <td class="daughter daughter-left"><table class="constituent lex" data-token="," data-from="13" data-to="14" data-cat="(NP\NP)/NP"> <tr><td class="token">,</td></tr> <tr><td class="cat" tabindex="0">(NP\NP)/NP</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> <td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[adj]\NP"> <tr class="daughters"> <td class="daughter daughter-left"><table class="constituent lex" data-token="nicht" data-from="15" data-to="20" data-cat="(S[adj]\NP)/(S[adj]\NP)"> <tr><td class="token">nicht</td></tr> <tr><td class="cat" tabindex="0">(S[adj]\NP)/(S[adj]\NP)</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> <td class="daughter daughter-right"><table class="constituent lex" data-token="wahr" data-from="21" data-to="25" data-cat="S[adj]\NP"> <tr><td class="token">wahr</td></tr> <tr><td class="cat" tabindex="0">S[adj]\NP</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> </tr> <tr><td colspan="2" class="rulecat"><div class="rulecat"> <div class="cat">S[adj]\NP</div> <div class="rule" title="Forward Application">> <sup>0</sup> </div> </div></td></tr> </table></td> </tr> <tr><td colspan="2" class="rulecat"><div class="rulecat"> <div class="cat">(S[adj]\NP)/NP</div> <div class="rule" title="Backward Composition">< <sup><i>n</i></sup> </div> </div></td></tr> </table></td> <td class="daughter daughter-right"><table class="constituent lex" data-token="?" data-from="25" data-to="26" data-cat="NP\NP"> <tr><td class="token">?</td></tr> <tr><td class="cat" tabindex="0">NP\NP</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> </tr> <tr><td colspan="2" class="rulecat"><div class="rulecat"> <div class="cat">(S[adj]\NP)\NP</div> <div class="rule" title="Forward Crossed Composition">> <sup>1</sup><sub>×</sub> </div> </div></td></tr> </table></td> </tr> <tr><td colspan="2" class="rulecat"><div class="rulecat"> <div class="cat">S[adj]\NP</div> <div class="rule" title="Backward Application">< <sup>0</sup> </div> </div></td></tr> </table></td> </tr> <tr><td colspan="2" class="rulecat"><div class="rulecat"> <div class="cat">S[dcl]\NP</div> <div class="rule" title="Forward Application">> <sup>0</sup> </div> </div></td></tr> </table></td> </tr> <tr><td colspan="2" class="rulecat"><div class="rulecat"> <div class="cat">S[dcl]</div> <div class="rule" title="Backward Application">< <sup>0</sup> </div> </div></td></tr> </table> </div>
Use with
der.css
.
\begin{tikzpicture}[ampersand replacement=\&] \matrix [column sep=9pt] at (0, 0) { \lexnode*{idm8}{Du}{\catNP}{} \& \lexnode*{idm23}{kannst}{(\catS[dcl]\?\catNP)/(\catS[adj]\?\catNP)}{} \& \lexnode*{idm44}{das}{\catNP}{} \& \lexnode*{idm70}{,}{(\catNP\?\catNP)/\catNP}{} \& \lexnode*{idm89}{nicht}{(\catS[adj]\?\catNP)/(\catS[adj]\?\catNP)}{} \& \lexnode*{idm103}{wahr}{\catS[adj]\?\catNP}{} \& \lexnode*{idm113}{?}{\catNP\?\catNP}{} \\ }; \binnode*{idm82}{idm89-cat}{idm103-cat}{\FC{0}}{\catS[adj]\?\catNP}{} \binnode*{idm61}{idm70-cat}{idm82}{\BC{n}}{(\catS[adj]\?\catNP)/\catNP}{} \binnode*{idm52}{idm61}{idm113-cat}{\FXC{1}}{(\catS[adj]\?\catNP)\?\catNP}{} \binnode*{idm37}{idm44-cat}{idm52}{\BC{0}}{\catS[adj]\?\catNP}{} \binnode*{idm16}{idm23-cat}{idm37}{\FC{0}}{\catS[dcl]\?\catNP}{} \binnode*{idm3}{idm8-cat}{idm16}{\BC{0}}{\catS[dcl]}{} \end{tikzpicture}
Use with
ccgsym.sty
and
tikzlibraryccgder.code.tex
.
Translations
eng
You can do it, can't you?
ita
Riesci a farla, vero?