Sentence


Parse

Es
NP
 
würde
(S[dcl]\NP)/(S[b]\NP)
 
ewig
(S[b]\NP)/(S[b]\NP)
 
dauern
S[b]\NP
 
S[b]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0
,
(NP\NP)/NP
 
alles
NP
 
NP\NP
> 0
zu
(S[to]\NP)/(S[b]\NP)
 
erklären
S[b]\NP
 
S[to]\NP
> 0
S[to]\NP
< 1
S[dcl]/S[dcl]
*
.
S[dcl]\S[dcl]
 
S[dcl]\S[dcl]
> 1×
S[dcl]
< 0

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