Sentence


Parse

Es
NP
 
wird
(S[dcl]\NP)/(S[b]\NP)
 
einen
NP/N
 
Wolkenbruch
N
 
NP
> 0
geben
(S[b]\NP)\NP
 
S[b]\NP
< 0
S[dcl]\NP
> 0
S[dcl]
< 0
.
S[dcl]\S[dcl]
 
S[dcl]
< 0

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