Sentence


Parse

Hast
(S[dcl]/NP)/(S[b]\NP)
 
du
NP
 
S[dcl]\(S[dcl]/NP)
T <
S[dcl]/(S[b]\NP)
< 1×
Lust
(S[b]\NP)/NP
 
,
NP/NP
 
etwas
NP
 
NP
> 0
S[b]\NP
> 0
S[dcl]
> 0
zu
(S[to]\NP)/(S[b]\NP)
 
essen
S[b]\NP
 
S[to]\NP
> 0
S[dcl]/S[dcl]
*
?
S[dcl]\S[dcl]
 
S[dcl]\S[dcl]
> 1×
S[dcl]
< 0

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