Sentence


Parse

Lass
(S[q]/(S[b]\NP))/NP
 
Vorsicht
N
 
NP
*
NP/(NP\NP)
T >
(S[q]/(S[b]\NP))/(NP\NP)
> 1
walten
S[b]\NP
 
S[q]\(S[q]/(S[b]\NP))
T <
S[q]/(NP\NP)
< 1×
!
NP\NP
 
S[q]
> 0

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