Sentence


Parse

Tom
N
 
NP
*
scheint
(S[dcl]\NP)/NP
 
seinen
NP/(N/PP)
 
Schlüssel
N/PP
 
NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0
verloren
S[pss]\NP
 
S[dcl]/S[dcl]
*
zu
(S[to]\NP)/(S[b]\NP)
 
haben
S[b]\NP
 
S[to]\NP
> 0
S[dcl]/S[dcl]
*
.
S[dcl]\S[dcl]
 
S[dcl]\S[dcl]
> 1×
S[dcl]\S[dcl]
> 1×
S[dcl]
< 0

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