Sentence


Parse

Um
N
 
wie
(N\N)/NP
 
viel~Uhr
N
 
NP
*
S[dcl]/(S[dcl]\NP)
T >
kommt
(S[dcl]\NP)/NP
 
S[dcl]/NP
> 1
N\N
*
(N\N)/NP
< n
der
NP/N
 
nächste
N/N
 
Zug
N
 
N
> 0
NP
> 0
N\N
> 0
N
< 0
NP
*
NP/(NP\NP)
T >
an
S[b]\NP
 
S[b]/(NP\NP)
< 1×
?
NP\NP
 
S[b]
> 0

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