Sentence


Parse

Wie
NP/N
 
lange
S[adj]\NP
 
N/N
*
NP/N
> 1
sind
(S[dcl]/(S[pt]\NP))/NP
 
Sie
NP
 
S[dcl]/(S[pt]\NP)
> 0
schon
(S[pt]\NP)/PP
 
in
PP/NP
 
Kōbe
N
 
NP\(NP/N)
T <
PP\(NP/N)
> 1×
(S[pt]\NP)\(NP/N)
> 1×
S[dcl]\(NP/N)
> 1×
S[dcl]
< 0
?
S[dcl]\S[dcl]
 
S[dcl]
< 0

Use with der.css.

Use with ccgsym.sty and tikzlibraryccgder.code.tex.


Translations