Sentence


Parse

A
NP/N
 
new
N/N
 
difficulty
N
 
N
> 0
NP
> 0
has
(S[dcl]\NP)/(S[pt]\NP)
 
arisen
S[pt]\NP
 
S[dcl]\NP
> 0
.
.
 
S[dcl]\NP
.
S[dcl]
< 0

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