Sentence


Parse

A
NP/N
 
word
N
 
NP
> 0
is
(S[dcl]\NP)/(S[adj]\NP)
 
enough
(S[adj]\NP)/PP
 
to
PP/NP
 
a
NP/N
 
wise
N/N
 
man
N
 
N
> 0
NP
> 0
.
.
 
NP
.
PP
> 0
S[adj]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0

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