Sentence


Parse

A
NP/N
 
word
N/PP
 
to
PP/NP
 
the
NP/N
 
wise
N
 
NP
> 0
PP
> 0
N
> 0
NP
> 0
is
(S[dcl]\NP)/(S[adj]\NP)
 
sufficient
S[adj]\NP
 
.
.
 
S[adj]\NP
.
S[dcl]\NP
> 0
S[dcl]
< 0

Use with der.css.

Use with ccgsym.sty and tikzlibraryccgder.code.tex.