Sentence


Parse

Ca
(S[q]/(S[b]\NP))/NP
 
n't
S\S
 
(S[q]/(S[b]\NP))/NP
< n×
we
NP
 
S[q]/(S[b]\NP)
> 0
break
(S[b]\NP)/NP
 
it
NP
 
S[b]\NP
> 0
?
.
 
S[b]\NP
.
S[q]
> 0

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