Sentence


Parse

Can
(S[q]/(S[b]\NP))/NP
 
I
NP
 
S[q]/(S[b]\NP)
> 0
speak
(S[b]\NP)/PP
 
to
PP/NP
 
you
NP
 
PP
> 0
S[b]\NP
> 0
in
((S\NP)\(S\NP))/NP
 
private
N
 
NP
*
?
.
 
NP
.
(S\NP)\(S\NP)
> 0
S[b]\NP
< 0
S[q]
> 0

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