Sentence


Parse

Did
(S[q]/(S[b]\NP))/NP
 
you
NP
 
S[q]/(S[b]\NP)
> 0
get
(S[b]\NP)/PP
 
in
PP/NP
 
touch
N
 
with
(N\N)/NP
 
her
NP
 
?
.
 
NP
.
N\N
> 0
N
< 0
NP
*
PP
> 0
S[b]\NP
> 0
S[q]
> 0

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