Sentence


Parse

Did
(S[q]/(S[b]\NP))/NP
 
you
NP
 
S[q]/(S[b]\NP)
> 0
get
(S[b]\NP)/NP
 
my
NP/(N/PP)
 
email
N/PP
 
yesterday
(N/PP)\(N/PP)
 
N/PP
< 0
NP
> 0
S[b]\NP
> 0
with
((S\NP)\(S\NP))/NP
 
the
NP/N
 
instructions
N
 
NP
> 0
?
.
 
NP
.
(S\NP)\(S\NP)
> 0
S[b]\NP
< 0
S[q]
> 0

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