Sentence


Parse

Did
(S[q]/(S[b]\NP))/NP
 
n't
S\S
 
(S[q]/(S[b]\NP))/NP
< n×
you
NP
 
S[q]/(S[b]\NP)
> 0
know
(S[b]\NP)/S[dcl]
 
Tom
N
 
NP
*
had
(S[dcl]\NP)/NP
 
a
NP/N
 
house
N
 
in
(N\N)/NP
 
Boston
N
 
NP
*
?
.
 
NP
.
N\N
> 0
N
< 0
NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0
S[b]\NP
> 0
S[q]
> 0

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