Sentence


Parse

Did
(S[q]/(S[b]\NP))/NP
 
n't
S\S
 
(S[q]/(S[b]\NP))/NP
< n×
you
NP
 
S[q]/(S[b]\NP)
> 0
know
(S[b]\NP)/S[dcl]
 
Tom
N
 
NP
*
was
(S[dcl]\NP)/(S[adj]\NP)
 
n't
(S\NP)\(S\NP)
 
(S[dcl]\NP)/(S[adj]\NP)
< 1×
happy
S[adj]\NP
 
here
(S\NP)\(S\NP)
 
?
.
 
(S\NP)\(S\NP)
.
S[adj]\NP
< 0
S[dcl]\NP
> 0
S[dcl]
< 0
S[b]\NP
> 0
S[q]
> 0

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