Sentence


Parse

Do
(S[q]/(S[b]\NP))/NP
 
you
NP
 
S[q]/(S[b]\NP)
> 0
know
(S[b]\NP)/NP
 
what
NP/(S[dcl]/NP)
 
Tom
N
 
NP
*
S[X]/(S[X]\NP)
T >
is
(S[dcl]\NP)/(S[ng]\NP)
 
doing
(S[ng]\NP)/NP
 
(S[dcl]\NP)/NP
> 1
?
.
 
(S[dcl]\NP)/NP
.
S[dcl]/NP
> 1
NP
> 0
S[b]\NP
> 0
S[q]
> 0

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