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Sentence
ara
bul
dan
eng
est
deu
fra
hin
ind
ita
kan
ltz
mar
nld
pol
por
ron
rus
spa
srp
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Go
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Does
(S[q]/(S[b]\NP))/NP
he
NP
S[q]/(S[b]\NP)
>
0
have
(S[b]\NP)/NP
money
N
NP
*
?
.
NP
.
S[b]\NP
>
0
S[q]
>
0
<div class="der"> <table class="constituent binaryrule" data-cat="S[q]"> <tr class="daughters"> <td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="S[q]/(S[b]\NP)"> <tr class="daughters"> <td class="daughter daughter-left"><table class="constituent lex" data-token="Does" data-from="0" data-to="4" data-cat="(S[q]/(S[b]\NP))/NP"> <tr><td class="token">Does</td></tr> <tr><td class="cat" tabindex="0">(S[q]/(S[b]\NP))/NP</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> <td class="daughter daughter-right"><table class="constituent lex" data-token="he" data-from="5" data-to="7" data-cat="NP"> <tr><td class="token">he</td></tr> <tr><td class="cat" tabindex="0">NP</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> </tr> <tr><td colspan="2" class="rulecat"><div class="rulecat"> <div class="cat">S[q]/(S[b]\NP)</div> <div class="rule" title="Forward Application">> <sup>0</sup> </div> </div></td></tr> </table></td> <td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[b]\NP"> <tr class="daughters"> <td class="daughter daughter-left"><table class="constituent lex" data-token="have" data-from="8" data-to="12" data-cat="(S[b]\NP)/NP"> <tr><td class="token">have</td></tr> <tr><td class="cat" tabindex="0">(S[b]\NP)/NP</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> <td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="NP"> <tr class="daughters"> <td class="daughter daughter-left"><table class="constituent unaryrule" data-cat="NP"> <tr class="daughters"><td class="daughter daughter-only"><table class="constituent lex" data-token="money" data-from="13" data-to="18" data-cat="N"> <tr><td class="token">money</td></tr> <tr><td class="cat" tabindex="0">N</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td></tr> <tr><td class="rulecat"><div class="rulecat"> <div class="cat">NP</div> <div class="rule" title="Type Changing"> * </div> </div></td></tr> </table></td> <td class="daughter daughter-right"><table class="constituent lex" data-token="?" data-from="18" data-to="19" data-cat="."> <tr><td class="token">?</td></tr> <tr><td class="cat" tabindex="0">.</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> </tr> <tr><td colspan="2" class="rulecat"><div class="rulecat"> <div class="cat">NP</div> <div class="rule" title="Remove Punctuation">.</div> </div></td></tr> </table></td> </tr> <tr><td colspan="2" class="rulecat"><div class="rulecat"> <div class="cat">S[b]\NP</div> <div class="rule" title="Forward Application">> <sup>0</sup> </div> </div></td></tr> </table></td> </tr> <tr><td colspan="2" class="rulecat"><div class="rulecat"> <div class="cat">S[q]</div> <div class="rule" title="Forward Application">> <sup>0</sup> </div> </div></td></tr> </table> </div>
Use with
der.css
.
\begin{tikzpicture}[ampersand replacement=\&] \matrix [column sep=9pt] at (0, 0) { \lexnode*{idm17}{Does}{(\catS[q]/(\catS[b]\?\catNP))/\catNP}{} \& \lexnode*{idm31}{he}{\catNP}{} \& \lexnode*{idm46}{have}{(\catS[b]\?\catNP)/\catNP}{} \& \lexnode*{idm66}{money}{\catN}{} \& \lexnode*{idm74}{?}{\cat.}{} \\ }; \binnode*{idm8}{idm17-cat}{idm31-cat}{\FC{0}}{\catS[q]/(\catS[b]\?\catNP)}{} \unnode*{idm63}{idm66-cat}{*}{\catNP}{} \binnode*{idm58}{idm63}{idm74-cat}{.}{\catNP}{} \binnode*{idm39}{idm46-cat}{idm58}{\FC{0}}{\catS[b]\?\catNP}{} \binnode*{idm3}{idm8}{idm39}{\FC{0}}{\catS[q]}{} \end{tikzpicture}
Use with
ccgsym.sty
and
tikzlibraryccgder.code.tex
.
Translations
deu
Hat er Geld?
fra
A-t-il de l'argent?
ita
Lui ha del denaro?
ita
Ha dei soldi?
ita
Ha del denaro?
ita
Lui ha dei soldi?
lat
Habetne pecuniam?
nld
Heeft hij geld?
por
Ele tem dinheiro?
rus
Деньги у него есть?
rus
У него есть деньги?
rus
У него деньги есть?
spa
¿Tiene dinero?
ukr
Він має гроші?
ukr
У нього є гроші?