Sentence


Parse

Do
(S[b]\NP)/(S[b]\NP)
 
n't
(S\NP)\(S\NP)
 
(S[b]\NP)/(S[b]\NP)
< 1×
let
((S[b]\NP)/(S[b]\NP))/NP
 
it
NP
 
(S[b]\NP)/(S[b]\NP)
> 0
get
(S[b]\NP)/PP
 
to
PP/NP
 
you
NP
 
PP
> 0
.
.
 
PP
.
S[b]\NP
> 0
S[b]\NP
> 0
S[b]\NP
> 0

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