Sentence


Parse

Do
(S[b]\NP)/(S[b]\NP)
 
n't
(S\NP)\(S\NP)
 
(S[b]\NP)/(S[b]\NP)
< 1×
underestimate
(S[b]\NP)/NP
 
(S[b]\NP)/NP
> 1
Tom
N
 
NP
*
S[X]/(S[X]\NP)
T >
's
N
 
coping
(S[ng]\NP)/NP
 
ability
N
 
NP
*
.
.
 
NP
.
S[ng]\NP
> 0
N\N
*
N
< 0
NP
*
(S[X]\NP)\((S[X]\NP)/NP)
T <
S[X]\((S[X]\NP)/NP)
> 1×
S[b]
< 0

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