Sentence


Parse

Do
(S[q]/(S[b]\NP))/NP
 
n't
S\S
 
(S[q]/(S[b]\NP))/NP
< n×
you
NP
 
S[q]/(S[b]\NP)
> 0
worry
(S[b]\NP)/PP
 
about
PP/NP
 
a
NP/N
 
thing
N
 
NP
> 0
.
.
 
NP
.
PP
> 0
S[b]\NP
> 0
S[q]
> 0

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