Sentence


Parse

Drop
(S[b]\NP)/NP
 
me
NP
 
S[X]/(S[X]\NP)
T >
a
NP/N
 
line
N
 
NP
> 0
(S[X]\NP)\((S[X]\NP)/NP)
T <
when
((S\NP)\(S\NP))/S[dcl]
 
you
NP
 
are
(S[dcl]\NP)/PP
 
in
PP/NP
 
trouble
N
 
NP
*
.
.
 
NP
.
PP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0
(S\NP)\(S\NP)
> 0
(S[X]\NP)\((S[X]\NP)/NP)
< 1
S[X]\((S[X]\NP)/NP)
> 1×
S[b]
< 0

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