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Finally
S/S
 
I
NP
 
have
(S[dcl]\NP)/NP
 
time
N/(S[to]\NP)
 
to
(S[to]\NP)/(S[b]\NP)
 
reply
(S[b]\NP)/PP
 
to
PP/NP
 
(S[b]\NP)/NP
> 1
(S[to]\NP)/NP
> 1
N/NP
> 1
the
NP/N
 
mail
N/N
 
I
NP
 
S[X]/(S[X]\NP)
T >
received
(S[dcl]\NP)/NP
 
S[dcl]/NP
> 1
N\N
*
N\N
> 1×
NP\N
> 1×
NP/NP
< 1×
these
NP/N
 
three
N/N
 
weeks
N
 
N
> 0
NP
> 0
.
.
 
NP
.
NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0
S[dcl]
> 0

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