Sentence


Parse

He
NP
 
does
(S[dcl]\NP)/(S[b]\NP)
 
n't
(S\NP)\(S\NP)
 
(S[dcl]\NP)/(S[b]\NP)
< 1×
listen
(S[b]\NP)/PP
 
to
PP/NP
 
anybody
NP
 
but
conj
 
himself
NP
 
NP\NP
.
.
 
NP\NP
.
NP
< 0
PP
> 0
S[b]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0

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