Sentence


Parse

He
NP
 
's
(S[dcl]\NP)/(S[adj]\NP)
 
new
S[adj]\NP
 
in
((S\NP)\(S\NP))/NP
 
town
N
 
NP
*
.
.
 
NP
.
(S\NP)\(S\NP)
> 0
S[adj]\NP
< 0
S[dcl]\NP
> 0
S[dcl]
< 0

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