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ara
bul
dan
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fra
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He
NP
is
(S[dcl]\NP)/(S[adj]\NP)
young
S[adj]\NP
,
,
S[adj]\NP
.
but
conj
experienced
S[adj]\NP
(S[adj]\NP)\(S[adj]\NP)
∨
.
.
(S[adj]\NP)\(S[adj]\NP)
.
S[adj]\NP
<
0
S[dcl]\NP
>
0
S[dcl]
<
0
<div class="der"> <table class="constituent binaryrule" data-cat="S[dcl]"> <tr class="daughters"> <td class="daughter daughter-left"><table class="constituent lex" data-token="He" data-from="0" data-to="2" data-cat="NP"> <tr><td class="token">He</td></tr> <tr><td class="cat" tabindex="0">NP</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> <td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[dcl]\NP"> <tr class="daughters"> <td class="daughter daughter-left"><table class="constituent lex" data-token="is" data-from="3" data-to="5" data-cat="(S[dcl]\NP)/(S[adj]\NP)"> <tr><td class="token">is</td></tr> <tr><td class="cat" tabindex="0">(S[dcl]\NP)/(S[adj]\NP)</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> <td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[adj]\NP"> <tr class="daughters"> <td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="S[adj]\NP"> <tr class="daughters"> <td class="daughter daughter-left"><table class="constituent lex" data-token="young" data-from="6" data-to="11" data-cat="S[adj]\NP"> <tr><td class="token">young</td></tr> <tr><td class="cat" tabindex="0">S[adj]\NP</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> <td class="daughter daughter-right"><table class="constituent lex" data-token="," data-from="11" data-to="12" data-cat=","> <tr><td class="token">,</td></tr> <tr><td class="cat" tabindex="0">,</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> </tr> <tr><td colspan="2" class="rulecat"><div class="rulecat"> <div class="cat">S[adj]\NP</div> <div class="rule" title="Remove Punctuation">.</div> </div></td></tr> </table></td> <td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="(S[adj]\NP)\(S[adj]\NP)"> <tr class="daughters"> <td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="(S[adj]\NP)\(S[adj]\NP)"> <tr class="daughters"> <td class="daughter daughter-left"><table class="constituent lex" data-token="but" data-from="13" data-to="16" data-cat="conj"> <tr><td class="token">but</td></tr> <tr><td class="cat" tabindex="0">conj</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> <td class="daughter daughter-right"><table class="constituent lex" data-token="experienced" data-from="17" data-to="28" data-cat="S[adj]\NP"> <tr><td class="token">experienced</td></tr> <tr><td class="cat" tabindex="0">S[adj]\NP</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> </tr> <tr><td colspan="2" class="rulecat"><div class="rulecat"> <div class="cat">(S[adj]\NP)\(S[adj]\NP)</div> <div class="rule" title="Conjunction">∨</div> </div></td></tr> </table></td> <td class="daughter daughter-right"><table class="constituent lex" data-token="." data-from="28" data-to="29" data-cat="."> <tr><td class="token">.</td></tr> <tr><td class="cat" tabindex="0">.</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> </tr> <tr><td colspan="2" class="rulecat"><div class="rulecat"> <div class="cat">(S[adj]\NP)\(S[adj]\NP)</div> <div class="rule" title="Remove Punctuation">.</div> </div></td></tr> </table></td> </tr> <tr><td colspan="2" class="rulecat"><div class="rulecat"> <div class="cat">S[adj]\NP</div> <div class="rule" title="Backward Application">< <sup>0</sup> </div> </div></td></tr> </table></td> </tr> <tr><td colspan="2" class="rulecat"><div class="rulecat"> <div class="cat">S[dcl]\NP</div> <div class="rule" title="Forward Application">> <sup>0</sup> </div> </div></td></tr> </table></td> </tr> <tr><td colspan="2" class="rulecat"><div class="rulecat"> <div class="cat">S[dcl]</div> <div class="rule" title="Backward Application">< <sup>0</sup> </div> </div></td></tr> </table> </div>
Use with
der.css
.
\begin{tikzpicture}[ampersand replacement=\&] \matrix [column sep=9pt] at (0, 0) { \lexnode*{idm8}{He}{\catNP}{} \& \lexnode*{idm23}{is}{(\catS[dcl]\?\catNP)/(\catS[adj]\?\catNP)}{} \& \lexnode*{idm51}{young}{\catS[adj]\?\catNP}{} \& \lexnode*{idm61}{,}{\cat,}{} \& \lexnode*{idm91}{but}{\catconj}{} \& \lexnode*{idm99}{experienced}{\catS[adj]\?\catNP}{} \& \lexnode*{idm109}{.}{\cat.}{} \\ }; \binnode*{idm44}{idm51-cat}{idm61-cat}{.}{\catS[adj]\?\catNP}{} \binnode*{idm80}{idm91-cat}{idm99-cat}{\wedge}{(\catS[adj]\?\catNP)\?(\catS[adj]\?\catNP)}{} \binnode*{idm69}{idm80}{idm109-cat}{.}{(\catS[adj]\?\catNP)\?(\catS[adj]\?\catNP)}{} \binnode*{idm37}{idm44}{idm69}{\BC{0}}{\catS[adj]\?\catNP}{} \binnode*{idm16}{idm23-cat}{idm37}{\FC{0}}{\catS[dcl]\?\catNP}{} \binnode*{idm3}{idm8-cat}{idm16}{\BC{0}}{\catS[dcl]}{} \end{tikzpicture}
Use with
ccgsym.sty
and
tikzlibraryccgder.code.tex
.
Translations
deu
Er ist jung, aber erfahren.
fra
Il est jeune mais a de l'expérience.
nld
Hij is jong, maar ervaren.
por
Ele é jovem, mas tem experiência.
rus
Он молодой, но опытный.
rus
Он молод, но опытен.
spa
Él es joven, pero tiene experiencia.