Sentence


Parse

How
S[wq]/S[q]
 
could
(S[q]/(S[b]\NP))/NP
 
you
NP
 
S[q]/(S[b]\NP)
> 0
do
((S[b]\NP)/PP)/NP
 
this
NP
 
(S[b]\NP)/PP
> 0
to
PP/NP
 
me
NP
 
PP
> 0
?
.
 
PP
.
S[b]\NP
> 0
S[q]
> 0
S[wq]
> 0

Use with der.css.

Use with ccgsym.sty and tikzlibraryccgder.code.tex.