Sentence


Parse

How
S[wq]/S[q]
 
do
(S[q]/(S[b]\NP))/NP
 
you
NP
 
S[q]/(S[b]\NP)
> 0
say
(S[b]\NP)/NP
 
that
NP
 
S[b]\NP
> 0
in
((S\NP)\(S\NP))/NP
 
Dutch
N
 
NP
*
?
.
 
NP
.
(S\NP)\(S\NP)
> 0
S[b]\NP
< 0
S[q]
> 0
S[wq]
> 0

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