Sentence


Parse

How
S[wq]/S[q]
 
's
S[adj]\NP
 
that
NP
 
S[X]/(S[X]\NP)
T >
again
(S\NP)\(S\NP)
 
?
.
 
(S\NP)\(S\NP)
.
S[X]\(S\NP)
> 1×
S[X]
< 0
S[wq]
> 0

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