Sentence


Parse

How
S[wq]/S[q]
 
's
(S[q]/(S[ng]\NP))/NP
 
your
NP/(N/PP)
 
old
N/N
 
man
N/PP
 
N/PP
> 1
NP
> 0
S[q]/(S[ng]\NP)
> 0
doing
S[ng]\NP
 
?
.
 
S[ng]\NP
.
S[q]
> 0
S[wq]
> 0

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