Sentence


Parse

How
(S/S)/(S[adj]\NP)
 
far
S[adj]\NP
 
S/S
> 0
is
(S[dcl]\NP)/PP
 
it
NP
 
S[X]/(S[X]\NP)
T >
from
PP/(S[adj]\NP)
 
here
S[adj]\NP
 
?
.
 
S[adj]\NP
.
PP
> 0
(S[X]\NP)\((S[X]\NP)/PP)
T <
S[X]\((S[X]\NP)/PP)
> 1×
S[dcl]
< 0
S[dcl]
> 0

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