Sentence


Parse

How
(S/S)/S[dcl]
 
many
N
 
NP
*
squares
S[dcl]\NP
 
S[dcl]
< 0
S/S
> 0
can
(S[q]/(S[b]\NP))/NP
 
you
NP
 
S[q]/(S[b]\NP)
> 0
see
S[b]\NP
 
?
.
 
S[b]\NP
.
S[q]
> 0
S[q]
> 0

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