Sentence


Parse

I
NP
 
am
(S[dcl]\NP)/(S[ng]\NP)
 
looking
(S[ng]\NP)/PP
 
forward
(S\NP)\(S\NP)
 
(S[ng]\NP)/PP
< 1×
to
PP/(S[ng]\NP)
 
seeing
(S[ng]\NP)/NP
 
you
NP
 
S[ng]\NP
> 0
again
(S\NP)\(S\NP)
 
.
.
 
(S\NP)\(S\NP)
.
S[ng]\NP
< 0
PP
> 0
S[ng]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0

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