Sentence


Parse

I
NP
 
do
(S[dcl]\NP)/(S[b]\NP)
 
n't
(S\NP)\(S\NP)
 
(S[dcl]\NP)/(S[b]\NP)
< 1×
know
(S[b]\NP)/NP
 
what
NP/(S[dcl]/NP)
 
(S[b]\NP)/(S[dcl]/NP)
> 1
else
S\S
 
(S[b]\NP)/(S[dcl]/NP)
< n
I
NP
 
S[X]/(S[X]\NP)
T >
can
(S[dcl]\NP)/(S[b]\NP)
 
say
(S[b]\NP)/NP
 
.
.
 
(S[b]\NP)/NP
.
(S[dcl]\NP)/NP
> 1
S[dcl]/NP
> 1
S[b]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0

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