Sentence


Parse

I
NP
 
do
(S[dcl]\NP)/(S[b]\NP)
 
n't
(S\NP)\(S\NP)
 
(S[dcl]\NP)/(S[b]\NP)
< 1×
understand
(S[b]\NP)/NP
 
this
NP
 
.
.
 
NP
.
S[b]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0

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