Sentence


Parse

I
NP
 
do
(S[dcl]\NP)/(S[b]\NP)
 
n't
(S\NP)\(S\NP)
 
(S[dcl]\NP)/(S[b]\NP)
< 1×
wear
(S[b]\NP)/NP
 
shoes
N
 
NP
*
S[b]\NP
> 0
in
((S\NP)\(S\NP))/NP
 
my
NP/(N/PP)
 
house
N/PP
 
NP
> 0
.
.
 
NP
.
(S\NP)\(S\NP)
> 0
S[b]\NP
< 0
S[dcl]\NP
> 0
S[dcl]
< 0

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