Sentence


Parse

I
NP
 
have
(S[dcl]\NP)/(S[to]\NP)
 
to
(S[to]\NP)/(S[b]\NP)
 
make
(S[b]\NP)/NP
 
a
NP/N
 
decision
N
 
NP
> 0
.
.
 
NP
.
S[b]\NP
> 0
S[to]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0

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