Sentence


Parse

I
NP
 
have
(S[dcl]\NP)/(S[to]\NP)
 
to
(S[to]\NP)/(S[b]\NP)
 
pay
((S[b]\NP)/PP)/NP
 
more
N/N
 
attention
N
 
N
> 0
NP
*
(S[b]\NP)/PP
> 0
to
PP/NP
 
myself
NP
 
PP
> 0
.
.
 
PP
.
S[b]\NP
> 0
S[to]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0

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