Sentence


Parse

I
NP
 
think
(S[dcl]\NP)/S[dcl]
 
I
NP
 
'm
(S[dcl]\NP)/PP
 
already
(S\NP)\(S\NP)
 
(S[dcl]\NP)/PP
< 1×
in
PP/NP
 
love
N/PP
 
with
PP/NP
 
you
NP
 
PP
> 0
.
.
 
PP
.
N
> 0
NP
*
PP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0
S[dcl]\NP
> 0
S[dcl]
< 0

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