CCGWeb - I want him to go there.

want

((S[dcl]\NP)/(S[to]\NP))/NP

him

(S[dcl]\NP)/(S[to]\NP)

> ⁰

(S[to]\NP)/(S[b]\NP)

S[b]\NP

S[to]\NP

> ⁰

S[dcl]\NP

> ⁰

there

(S\NP)\(S\NP)

S[dcl]\NP

< ⁰

S[dcl]

< ⁰

 <div class="der">
<table class="constituent binaryrule" data-cat="S[dcl]">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="I" data-from="0" data-to="1" data-cat="NP">
<tr><td class="token">I</td></tr>
<tr><td class="cat" tabindex="0">NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[dcl]\NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="S[dcl]\NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="(S[dcl]\NP)/(S[to]\NP)">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="want" data-from="2" data-to="6" data-cat="((S[dcl]\NP)/(S[to]\NP))/NP">
<tr><td class="token">want</td></tr>
<tr><td class="cat" tabindex="0">((S[dcl]\NP)/(S[to]\NP))/NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="him" data-from="7" data-to="10" data-cat="NP">
<tr><td class="token">him</td></tr>
<tr><td class="cat" tabindex="0">NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">(S[dcl]\NP)/(S[to]\NP)</div>
<div class="rule" title="Forward Application">&gt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[to]\NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="to" data-from="11" data-to="13" data-cat="(S[to]\NP)/(S[b]\NP)">
<tr><td class="token">to</td></tr>
<tr><td class="cat" tabindex="0">(S[to]\NP)/(S[b]\NP)</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="go" data-from="14" data-to="16" data-cat="S[b]\NP">
<tr><td class="token">go</td></tr>
<tr><td class="cat" tabindex="0">S[b]\NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[to]\NP</div>
<div class="rule" title="Forward Application">&gt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]\NP</div>
<div class="rule" title="Forward Application">&gt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="(S\NP)\(S\NP)">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="there" data-from="17" data-to="22" data-cat="(S\NP)\(S\NP)">
<tr><td class="token">there</td></tr>
<tr><td class="cat" tabindex="0">(S\NP)\(S\NP)</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="." data-from="22" data-to="23" data-cat=".">
<tr><td class="token">.</td></tr>
<tr><td class="cat" tabindex="0">.</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">(S\NP)\(S\NP)</div>
<div class="rule" title="Remove Punctuation">.</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]\NP</div>
<div class="rule" title="Backward Application">&lt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]</div>
<div class="rule" title="Backward Application">&lt; <sup>0</sup>
</div>
</div></td></tr>
</table> </div>

Use with der.css.

\begin{tikzpicture}[ampersand replacement=\&]
	\matrix [column sep=9pt] at (0, 0) {
		\lexnode*{idm8}{I}{\catNP}{} \&
		\lexnode*{idm41}{want}{((\catS[dcl]\?\catNP)/(\catS[to]\?\catNP))/\catNP}{} \&
		\lexnode*{idm57}{him}{\catNP}{} \&
		\lexnode*{idm72}{to}{(\catS[to]\?\catNP)/(\catS[b]\?\catNP)}{} \&
		\lexnode*{idm86}{go}{\catS[b]\?\catNP}{} \&
		\lexnode*{idm107}{there}{(\catS\?\catNP)\?(\catS\?\catNP)}{} \&
		\lexnode*{idm121}{.}{\cat.}{} \\
	};
	\binnode*{idm30}{idm41-cat}{idm57-cat}{\FC{0}}{(\catS[dcl]\?\catNP)/(\catS[to]\?\catNP)}{}
	\binnode*{idm65}{idm72-cat}{idm86-cat}{\FC{0}}{\catS[to]\?\catNP}{}
	\binnode*{idm23}{idm30}{idm65}{\FC{0}}{\catS[dcl]\?\catNP}{}
	\binnode*{idm96}{idm107-cat}{idm121-cat}{.}{(\catS\?\catNP)\?(\catS\?\catNP)}{}
	\binnode*{idm16}{idm23}{idm96}{\BC{0}}{\catS[dcl]\?\catNP}{}
	\binnode*{idm3}{idm8-cat}{idm16}{\BC{0}}{\catS[dcl]}{}
\end{tikzpicture}

Use with ccgsym.sty and tikzlibraryccgder.code.tex.

Sentence

Parse

Translations