Sentence


Parse

I
NP
 
'd
(S[dcl]\NP)/(S[b]\NP)
 
buy
(S[b]\NP)/NP
 
it
NP
 
S[b]\NP
> 0
S[dcl]\NP
> 0
if
((S\NP)\(S\NP))/S[dcl]
 
I
NP
 
were
S[dcl]\NP
 
S[dcl]
< 0
(S\NP)\(S\NP)
> 0
S[dcl]\NP
< 0
n't
(S\NP)\(S\NP)
 
S[dcl]\NP
< 0
broke
(S\NP)\(S\NP)
 
.
.
 
(S\NP)\(S\NP)
.
S[dcl]\NP
< 0
S[dcl]
< 0

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