Sentence


Parse

I
NP
 
'll
(S[dcl]\NP)/(S[b]\NP)
 
let
((S[b]\NP)/(S[b]\NP))/NP
 
you
NP
 
(S[b]\NP)/(S[b]\NP)
> 0
know
S[b]\NP
 
S[b]\NP
> 0
S[dcl]\NP
> 0
as
((S\NP)\(S\NP))/((S\NP)\(S\NP))
 
soon
(S\NP)\(S\NP)
 
as
(((S\NP)\(S\NP))\((S\NP)\(S\NP)))/S[dcl]
 
I
NP
 
get
S[dcl]\NP
 
S[dcl]
< 0
((S\NP)\(S\NP))\((S\NP)\(S\NP))
> 0
(S\NP)\(S\NP)
< 0
(S\NP)\(S\NP)
> 0
S[dcl]\NP
< 0
there
(S\NP)\(S\NP)
 
.
.
 
(S\NP)\(S\NP)
.
S[dcl]\NP
< 0
S[dcl]
< 0

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