Sentence


Parse

I
NP
 
'm
(S[dcl]\NP)/(S[ng]\NP)
 
having
(S[ng]\NP)/NP
 
a
NP/N
 
hard
N/N
 
time
N/(S[ng]\NP)
 
reading
(S[ng]\NP)/NP
 
it
NP
 
S[ng]\NP
> 0
N
> 0
N
> 0
NP
> 0
S[ng]\NP
> 0
.
.
 
S[ng]\NP
.
S[dcl]\NP
> 0
S[dcl]
< 0

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