CCGWeb - I'm not a bit tired.

(S[dcl]\NP)/(S[adj]\NP)

not

(S\NP)\(S\NP)

(S[dcl]\NP)/(S[adj]\NP)

< ¹_×

((S[adj]\NP)/(S[adj]\NP))/((S[adj]\NP)/(S[adj]\NP))

bit

(S[adj]\NP)/(S[adj]\NP)

> ⁰

tired

S[adj]\NP

> ⁰

S[dcl]\NP

> ⁰

S[dcl]

< ⁰

 <div class="der">
<table class="constituent binaryrule" data-cat="S[dcl]">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="I" data-from="0" data-to="1" data-cat="NP">
<tr><td class="token">I</td></tr>
<tr><td class="cat" tabindex="0">NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[dcl]\NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="(S[dcl]\NP)/(S[adj]\NP)">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="'m" data-from="1" data-to="3" data-cat="(S[dcl]\NP)/(S[adj]\NP)">
<tr><td class="token">'m</td></tr>
<tr><td class="cat" tabindex="0">(S[dcl]\NP)/(S[adj]\NP)</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="not" data-from="4" data-to="7" data-cat="(S\NP)\(S\NP)">
<tr><td class="token">not</td></tr>
<tr><td class="cat" tabindex="0">(S\NP)\(S\NP)</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">(S[dcl]\NP)/(S[adj]\NP)</div>
<div class="rule" title="Backward Crossed Composition">&lt; <sup>1</sup><sub>×</sub>
</div>
</div></td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[adj]\NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="(S[adj]\NP)/(S[adj]\NP)">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="a" data-from="8" data-to="9" data-cat="((S[adj]\NP)/(S[adj]\NP))/((S[adj]\NP)/(S[adj]\NP))">
<tr><td class="token">a</td></tr>
<tr><td class="cat" tabindex="0">((S[adj]\NP)/(S[adj]\NP))/((S[adj]\NP)/(S[adj]\NP))</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="bit" data-from="10" data-to="13" data-cat="(S[adj]\NP)/(S[adj]\NP)">
<tr><td class="token">bit</td></tr>
<tr><td class="cat" tabindex="0">(S[adj]\NP)/(S[adj]\NP)</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">(S[adj]\NP)/(S[adj]\NP)</div>
<div class="rule" title="Forward Application">&gt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[adj]\NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="tired" data-from="14" data-to="19" data-cat="S[adj]\NP">
<tr><td class="token">tired</td></tr>
<tr><td class="cat" tabindex="0">S[adj]\NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="." data-from="19" data-to="20" data-cat=".">
<tr><td class="token">.</td></tr>
<tr><td class="cat" tabindex="0">.</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[adj]\NP</div>
<div class="rule" title="Remove Punctuation">.</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[adj]\NP</div>
<div class="rule" title="Forward Application">&gt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]\NP</div>
<div class="rule" title="Forward Application">&gt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]</div>
<div class="rule" title="Backward Application">&lt; <sup>0</sup>
</div>
</div></td></tr>
</table> </div>

Use with der.css.

\begin{tikzpicture}[ampersand replacement=\&]
	\matrix [column sep=9pt] at (0, 0) {
		\lexnode*{idm8}{I}{\catNP}{} \&
		\lexnode*{idm34}{'m}{(\catS[dcl]\?\catNP)/(\catS[adj]\?\catNP)}{} \&
		\lexnode*{idm48}{not}{(\catS\?\catNP)\?(\catS\?\catNP)}{} \&
		\lexnode*{idm80}{a}{((\catS[adj]\?\catNP)/(\catS[adj]\?\catNP))/((\catS[adj]\?\catNP)/(\catS[adj]\?\catNP))}{} \&
		\lexnode*{idm102}{bit}{(\catS[adj]\?\catNP)/(\catS[adj]\?\catNP)}{} \&
		\lexnode*{idm123}{tired}{\catS[adj]\?\catNP}{} \&
		\lexnode*{idm133}{.}{\cat.}{} \\
	};
	\binnode*{idm23}{idm34-cat}{idm48-cat}{\BXC{1}}{(\catS[dcl]\?\catNP)/(\catS[adj]\?\catNP)}{}
	\binnode*{idm69}{idm80-cat}{idm102-cat}{\FC{0}}{(\catS[adj]\?\catNP)/(\catS[adj]\?\catNP)}{}
	\binnode*{idm116}{idm123-cat}{idm133-cat}{.}{\catS[adj]\?\catNP}{}
	\binnode*{idm62}{idm69}{idm116}{\FC{0}}{\catS[adj]\?\catNP}{}
	\binnode*{idm16}{idm23}{idm62}{\FC{0}}{\catS[dcl]\?\catNP}{}
	\binnode*{idm3}{idm8-cat}{idm16}{\BC{0}}{\catS[dcl]}{}
\end{tikzpicture}

Use with ccgsym.sty and tikzlibraryccgder.code.tex.

Sentence

Parse

Translations