Sentence


Parse

I
NP
 
'm
(S[dcl]\NP)/(S[ng]\NP)
 
not
(S\NP)\(S\NP)
 
(S[dcl]\NP)/(S[ng]\NP)
< 1×
getting
(S[ng]\NP)/NP
 
this
NP
 
.
.
 
NP
.
S[ng]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0

Use with der.css.

Use with ccgsym.sty and tikzlibraryccgder.code.tex.